Answered

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(5x^5) - (80x^3)
factoring

Sagot :

absor201

Answer:

Factoring the term [tex](5x^5) - (80x^3)[/tex] we get [tex]\mathbf{5x^3(x-4)(x+4)}[/tex]

Step-by-step explanation:

We need to factor the term [tex](5x^5) - (80x^3)[/tex]

First we can see that [tex]5x^3[/tex] is common in both terms

So, taking [tex]5x^3[/tex] common:

[tex](5x^5) - (80x^3)\\=5x^3(x^2-16)[/tex]

We can write [tex]x^2-16[/tex] as [tex](x)^2-(4)^2[/tex]

[tex]=5x^3((x)^2-(4)^2)[/tex]

Now we can solve [tex](x)^2-(4)^2[/tex] using the formula: [tex]a^2-b^2=(a+b)(a-b)[/tex]

We can write:

[tex]=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)[/tex]

So, factoring the term [tex](5x^5) - (80x^3)[/tex] we get [tex]\mathbf{5x^3(x-4)(x+4)}[/tex]

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