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how do i write an equation in point-slope form for a horizontal line that passes through(4, –2)??

Sagot :

Answer:

[tex]y = -2[/tex]

Step-by-step explanation:

Given

Horizontal Line

[tex](x_1,y_1) = (4,-2)[/tex]

Required

Determine the equation

The equation is calculated using:

[tex]y - y_1 =m(x-x_1)[/tex]

Where

[tex]m = slope[/tex]

Because the line is a horizontal line, then:

[tex]m = 0[/tex]

Substitute 0 for m and values for x1 and y1 in [tex]y - y_1 =m(x-x_1)[/tex]

[tex]y - (-2) = 0(x -4)[/tex]

[tex]y +2 = 0(x -4)[/tex]

[tex]y +2 = 0[/tex]

Subtract 2 from both sides

[tex]y +2-2 = 0-2[/tex]

[tex]y = -2[/tex]

Hence, the equation is: [tex]y = -2[/tex]