Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
There's a constant force of 35 N exerted on the object of mass 2.0 kg, so it undergoes an acceleration a of
35 N = (2.0 kg) a → a = 17.5 m/s²
The object travels 8.0 m, so that it attains a velocity v of
v ² = 2 (17.5 m/s²) (8.0 m) → v ≈ 16.73 m/s ≈ 17 m/s
The velocity of the 2 Kg object which travels 8 m along the horizontal frictionless surface is 17 m/s
How to determine the acceleration
- Force (F) = 35 N
- Mass (m) = 2 Kg
- Acceleration (a) =?
a = F / m
a = 35 / 2
a = 17.5 m/s²
How to determine the velocity
- Initial velocity (u) = 0 m/s
- Distance (s) = 8 m
- Acceleration (a) = 17.5 m/s²
- Final velocity (v) =?
v² = u² + 2as
v² = 0² + (2 × 17.5 × 8)
v² = 280
Take the square root of both side
v = √280
v = 17 m/s
Learn more about velocity:
https://brainly.com/question/3411682
#SPJ2
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.