700271
Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A student draws a card at random from the
cards shown. Without replacing the card,
1
he draws a second card.
E
P
E
N
D
E
N
T
E
V
E
N
T
S
What is the probability that the student will
draw two consonants?
A
3
7
с
2
91
N
WN ON
B
1
35

A Student Draws A Card At Random From The Cards Shown Without Replacing The Card 1 He Draws A Second Card E P E N D E N T E V E N T S What Is The Probability Th class=

Sagot :

Answer:  Choice A. 3/7

===============================================

Explanation:

We have a 5 by 3 grid of letters. There are 5*3 = 15 letters total.

Of that total, there are 5 vowels (2 'e's in row 1, 2 'e's in row 2, and 1 'e' in row 3)

So there are 15-5 = 10 consonants.

The probability of pulling out a consonant is 10/15 = 2/3

After selecting that consonant, we have 10-1 = 9 consonants left out of 15-1 = 14 letters total.

The probability of selecting a second consonant, after not replacing the first selection, is 9/14.

Multiply the two fractions found:

(2/3)*(9/14) = (2*9)/(3*14) = 18/42 = 3/7

To reduce 18/42, we divide both parts by the GCF 6, which is how we end up with 3/7.

Obamatriangle
5/14 or 35% I think
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.