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Sagot :
Answer:
10.791 kJ
Explanation:
Given that,
Mass of the skier, m = 58 kg
Initial position, h₁ = 24 m
Final position, h₂ = 19 m
We need to find the kinetic energy do they have at the top of the second hill.
Using the conservation of energy for both positions.
[tex]v_1=\sqrt{2gh_1} \\\\=\sqrt{2\times 9.8\times 24} \\\\=21.68\ m/s[/tex]
And
[tex]v_2=\sqrt{2gh_2} \\\\=\sqrt{2\times 9.8\times 19} \\\\=19.29\ m/s[/tex]
Kinetic energy :
[tex]K=\dfrac{1}{2}mv_2^2\\\\K=\dfrac{1}{2}\times 58\times 19.29^2\\\\=10791.01 J\\\\=10.791\ kJ[/tex]
So, the kinetic energy they have at the top of the second hill is 10.791 kJ.
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