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A high school club has 10 members who are seniors and 8 members who
are juniors. If a member is randomly selected to be the club president,
what is the probability that the person will NOT be a senior?


Sagot :

Answer:

The probability that the person will not  be a senior

P(E⁻) = 1 - P(E)

       =  [tex]1- \frac{5}{9} = \frac{4}{9}[/tex]

Step-by-step explanation:

Explanation:-

Given A high school club has 10 members who are seniors and 8 members who  are juniors

n(S) = 10 + 8 = 18

If a member is randomly selected to be the club president

Let 'E' be the event that the person will  be a senior

The probability that the person will  be a senior

      [tex]P(E) = \frac{n(E)}{n(S)}[/tex]

     [tex]P(E) = \frac{n(E)}{n(S)} = \frac{10}{18} = \frac{5}{9}[/tex]

The probability that the person will not  be a senior

P(E⁻) = 1 - P(E)

       =  [tex]1- \frac{5}{9} = \frac{4}{9}[/tex]