Answer:
a) [tex]1\,cm^{2}[/tex] is [tex]\frac{1}{6}[/tex] of area A.
b) [tex]1\,cm^{2}[/tex] is [tex]\frac{1}{18}[/tex] of area B.
c) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{3}[/tex] of area C.
d) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{4}[/tex] of area D.
e) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{2}[/tex] of area E.
Step-by-step explanation:
According to stament, the area A is 6 square centimeters, the area B is 18 square centimeters, the area C is 3 square centimeters, the area D is 4 square centimeters and the area E is 2 square centimeters.
The purpose of this exercise is determine all ratios associated with each area, defined as a given area divided by the total area. Then, we proceed to determine each result:
([tex]A_{given} = 1\,cm^{2}[/tex], [tex]A_{A} = 6\,cm^{2}[/tex], [tex]A_{B} = 18\,cm^{2}[/tex], [tex]A_{C} = 3\,cm^{2}[/tex], [tex]A_{D} = 4\,cm^{2}[/tex], [tex]A_{E} = 2\,cm^{2}[/tex])
[tex]r_{A} = \frac{1\,cm^{2}}{6\,cm^{2}}[/tex]
[tex]r_{A} = \frac{1}{6}[/tex]
[tex]r_{B} = \frac{1\,cm^{2}}{18\,cm^{2}}[/tex]
[tex]r_{B} = \frac{1}{18}[/tex]
[tex]r_{C} = \frac{1\,cm^{2}}{3\,cm^{2}}[/tex]
[tex]r_{C} = \frac{1}{3}[/tex]
[tex]r_{D} = \frac{1\,cm^{2}}{4\,cm^{2}}[/tex]
[tex]r_{D} = \frac{1}{4}[/tex]
[tex]r_{E} = \frac{1\,cm^{2}}{2\,cm^{2}}[/tex]
[tex]r_{E} = \frac{1}{2}[/tex]
a) [tex]1\,cm^{2}[/tex] is [tex]\frac{1}{6}[/tex] of area A.
b) [tex]1\,cm^{2}[/tex] is [tex]\frac{1}{18}[/tex] of area B.
c) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{3}[/tex] of area C.
d) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{4}[/tex] of area D.
e) [tex]1\,cm^{2}[/tex] of [tex]\frac{1}{2}[/tex] of area E.
