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Consider function h. h(x)= 3x-4 x<0 2x^2-3x+10 0<=x<4 2^x x>=5 What are the values of the function when x=0 and when x=4?

Sagot :

xero099

Answer:

[tex]h(0) = 10[/tex]

[tex]h(4) = NaN[/tex] (Not a number)

Step-by-step explanation:

According to the statement, we get the following piecewise function:

[tex]h(x) = \left\{ \begin{array}{ccc}3\cdot x -4,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x < 0\\2\cdot x^{2}-3\cdot x + 10,\,\,\,\,\, 0\le x < 4\\2^{x}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, x\ge 5\end{array}[/tex]

The value of the function when [tex]x = 0[/tex] is:

[tex]h(0) = 2\cdot (0)^{3}-3\cdot (0) +10[/tex]

[tex]h(0) = 10[/tex]

The value of the function when [tex]x = 4[/tex] is undefined, since 4 is out of any of the intervals covered by [tex]h(x)[/tex].

[tex]h(4) = NaN[/tex] (Not a number)

Answer: h(0)=10

h(4)=30

Step-by-step explanation:

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