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Use the Law of Logarithm to expand the expression. ln(y √x/z (I know the answer is 2ln(y)+ln(x)-ln(z) all over 2, but I need the steps to get there)

Sagot :

okpalawalter8

Answer:

[tex]in (y\sqrt{\frac{x}{y}}) =\frac{1}{2} in(x)-\frac{1}{2} in(z) +in(y)[/tex]

Step-by-step explanation:

From the question we are told that the expression [tex]ln(y √x/z[/tex]

[tex]in (y\sqrt{\frac{x}{y}})[/tex]

[tex]in(y)+in(y\sqrt{\frac{x}{y}})[/tex]

[tex]in(xy)=in(x)+in(y)[/tex]

[tex]in(xy)=in\frac{x}{z} ^1^/^2 +in(y)[/tex]

[tex]in(xy)=\frac{1}{2} in(\frac{x}{z}) +in(y)[/tex]

[tex]in(xy)=\frac{1}{2} in(x)-in(z) +in(y)[/tex]

[tex]in(xy)=\frac{1}{2} in(x)-\frac{1}{2} in(z) +in(y)[/tex]

Mathematically

[tex]in (y\sqrt{\frac{x}{y}}) =\frac{1}{2} in(x)-\frac{1}{2} in(z) +in(y)[/tex]

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