Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Answer:
4/16 or 1/4
Explanation:
This question involves two genes; one coding for coat color and the other for pigment color. The allele for black coat color (B) is dominant to the allele for brown coat color (b) while two copies of the recessive allele for a pigment-depositing gene (e) can only have yellow coat color.
In a cross between two heterozygotes (BbEe), the following gametes will be produced by each parent: BE, Be, bE and be. Using these gametes in a punnet square (see attached image), the fraction of the next generation (F2) expected to be yellow i.e. have the genotype (__ee) will be 4/16 or 1/4.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.