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Sagot :
Answer:
The potential at the center of square due to four identical charges each at the corner is 5.09 q x [tex]10^1^0[/tex] Volts, where q is the charge.
Explanation:
From the question it is given that
side of square = a = 1 m
let the charge of each square is q
potential at center due to 1 charge is V = [tex]\frac{q}{4\pi \epsilon r}[/tex] , where
[tex]\epsilon[/tex] is electrical permittivity of space
r is the distance between charge and point.
since the charge is present at at the corner so the distance between charge and point is the half the length of diagonal of square.
⇒ distance between charge and point = r =[tex]\frac{a}{\sqrt{2}}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] = 0.707 m
thus, V= [tex]\frac{q}{4\pi \epsilon r}[/tex] , on substituting the respected values of r = 0.707m and [tex]\frac{1}{4\pi \epsilon}[/tex] = 9 x [tex]10^9[/tex] we get,
V = 1.272 q x [tex]10^1^0[/tex] V
thus potential due to all 4 charges is
V = 1.272 q x [tex]10^1^0[/tex] x 4 = 5.09 q x [tex]10^1^0[/tex] Volts
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