Answer:
9.11×10⁷ Hz
Explanation:
From the question given above the following data were obtained:
Energy (E) = 6.04×10¯²⁹ KJ
Frequency (f) =?
Next, we shall convert 6.04×10¯²⁹ KJ to joule (J). This can be obtained as follow:
1 KJ = 1000 J
Therefore,
6.04×10¯²⁹ KJ = 6.04×10¯²⁹ KJ × 1000 J / 1 KJ
6.04×10¯²⁹ KJ = 6.04×10¯²⁶ J
Thus, 6.04×10¯²⁹ KJ is equivalent to 6.04×10¯²⁶ J.
Finally, we shall determine the frequency at which the FM radio station is broadcasting as follow:
Energy (E) = 6.04×10¯²⁶ J
Planck's constant (h) = 6.63×10¯³⁴ Js
Frequency (f) =?
E = hf
6.04×10¯²⁶ = 6.63×10¯³⁴ × f
Divide both side by 6.63×10¯³⁴
f = 6.04×10¯²⁶ / 6.63×10¯³⁴
f = 9.11×10⁷ Hz
Therefore, the frequency at which the FM radio station is broadcasting is 9.11×10⁷ Hz
