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A compound is found to contain 25.24 % sulfur and 74.76 % fluorine by weight. To answer the questions, enter the elements in the order presented above. 1. What is the empirical formula for this compound

Sagot :

sebassandin

Answer:

[tex]SF_5[/tex]

Explanation:

Hello!

In this case, when determining empirical formulas by knowing the by-mass percent, we can first assume we have 25.24 g of sulfur and 74.76 g of fluorine, so we compute the moles:

[tex]n_S=25.24g*\frac{1mol}{32.07g} =0.787mol\\\\n_F=74.76g*\frac{1mol}{19.00g}= 3.935mol[/tex]

Now, we divide the moles of both S and F by the fewest moles, in this case, those of S in order to determine the subscripts in the empirical formula:

[tex]S=\frac{0.787}{0.797}=1 \\\\F=\frac{3.935}{0.797}=5[/tex]

Therefore, the empirical formula is:

[tex]SF_5[/tex]

Best regards!

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