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The intensity at a distance of 6 m from a source that is radiating equally in all directions is 6.0\times 10^{-10} W/m^2. What is the power emitted by the source

Sagot :

cjrodriguez89

Answer:

P = 271 nW

Explanation:

  • If the source is radiating equally in all directions, it can be treated as a point source, so all points located at the same distance of the source, have the same intensity I, which is related to the power by the following expression:

       [tex]I = \frac{P}{A} =\frac{P}{4*\pi *r^{2} } (1)[/tex]

  • Solving for P, we get:

       [tex]P = I*4*\pi *r^{2} = 6.0e-10 W/m2 * 4 * \pi *(6m)^{2} =271 nW (2)[/tex]

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