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Find the value of x using the pythagorean theorem.

Do the side lengths form a pythagorean triple?


Find The Value Of X Using The Pythagorean Theorem Do The Side Lengths Form A Pythagorean Triple class=

Sagot :

Answer:

[tex] {x}^{2} = {9}^{2} + {40}^{2} \\ {x}^{2} = 81 + 1600 \\ {x}^{2} = 1681 \\ x = \sqrt{1681} \\ x = 41[/tex]

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