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Sagot :

Answer:

[tex] \frac{y - 3}{x - 0} = \frac{3 - 1}{0 - 1} = \frac{2}{ - 1} \\ \frac{y - 3}{x} = - 2 \\ y - 3 = - 2x\\ 2x + y - 3 = 0 \\y = - 2x + 3 \\ \boxed{f(x) = - 2x + 3}[/tex]

B. is the right answer.

hope this helps.