Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution.

Sagot :

Answer:

only one solution

Step-by-step explanation:

Complete question:

Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 2x − y = 2 3x + y = −6 one and only one solution infinitely many solutions no solution Find the solution, if one exists. (If there are infinitely many solutions, express x and y in terms of the parameter t. If there is no solution, enter NO SOLUTION.) (x, y) =

Given the expression

2x − y = 2 .... 1

3x + y = −6  ..... 2

We are to determine the number of solution the equation has:

Add equation 1 and 2

2x + 3x = 2 - 6

5x = -4

x = -4/5

Substitute x = -4/5 into 1

From 1: 2x − y = 2 .... 1

2(-4/5) - y = 2

-8/5 - y = -2

-y = -2+8/5

-y = -10+8/5

-y = -2/5

y = 2/5

Since the value of x and y are just 1 hence the system of equations has ine solution