Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

A skateboarder traveling at 10.4 m/s starts getting chased by a grumpy dog. The skateboarder speeds up with a constant acceleration for 39m over a 3.3s. We want to find the acceleration of the skateboarder over the 3.3s time interval. Which kinematic formula would be most useful to solve for the target unknown?

a. V= Vo+a(t)
b. X= (V+Vo/2)t
c. X= Vo(t)+1/2at^2
d. V^2 = Vo^2 +2ax
e. X= vt-1/2at^2

Sagot :

okpalawalter8

Answer:

c)X= Vo(t)+1/2at^2

Explanation:

From the question we are told that

initial speed u=10.4

displacement d= 39

time t=3.3s

accelaration a=?

Generally the best equation in solving for Acceleration is given to be

X= Vo(t)+1/2at^2

Mathematically

     [tex]X= Vo(t)+1/2at^2[/tex]

     [tex]39=10.4t+\frac{a}{2} *3.3^2[/tex]

     [tex]5.445a=39-34.32[/tex]

     [tex]a=39-34.32/5.445[/tex]

     [tex]a=4.68/5.445[/tex]

     [tex]a=0.86m/s^2[/tex]

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.