RODRIJP866
Answered

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err i dont know U>U here you go peeps

Err I Dont Know UgtU Here You Go Peeps class=

Sagot :

manissaha129

Answer:

[tex] {x}^{2} + {y}^{2} + 4x - 2y = - 1 \\ ( {x}^{2}+2\times2\times x + {2}^{2} ) - 4 + ({y}^{2} - 2 \times 1 \times y + {1}^{2} ) - 1 = - 1 \\ {(x + 2)}^{2} - 4 + {(y - 1)}^{2} - 1 = - 1 \\ {(x + 2)}^{2} + {(y - 1)}^{2} = 4\\ {(x + 2)}^{2} + {(y - 1)}^{2} = {( 2) }^{2} [/tex]

Therefore, the centre of the circle is in ( -2, 1 )

and the radius of the circle is 2.

Formula used :-----

[tex] {(x - a)}^{2} + {(y - b)}^{2} = {r}^{2} [/tex]

equation of the circle

where r is the radius of the circle.

(A) 2 is the right answer.

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