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Sagot :
Answer:
y^8 goes to the last one
y^6 goes to the third one
y^5 goes to the second one
then the last one go to the first one
Answer:
(y)^-2 = 1/y^2, (y^3)^2 = y^6, y^8 -:- y^3 = y^5, and y^4 x y^4 = y^8
Step-by-step explanation:
When you divide y^8 -:- y^3, you subtract ^8-^3 = ^5, so its y^8 -:- y^3 = y^5
When you multiply y^4 x y^4, you add ^4 + ^4 = ^8, so it is y^4 x y^4 = y^8
When you multiply (y^3)^2, you multiply ^3 x ^2 = ^6, so its (y^3)^2 = y^6
And when you have a negative exponent,(^-2) you have to make it positive, so it would be y^-2 = 1/y^2
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