Answered

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Which answer shows this equation in standard form?

6 – 2(x – y) = –3x + 5

A.
x + 2y = –1

B.
x + 2y = 1

C.
x – 2y = 1

D.
–5x + 2y = –1

Sagot :


6-2(x-y)=-3x+5

6-2x+2y=-3x+5

6-2x+2x+2y=-3x+2x+5

6+2y=-x+5

6-6+2y=-x+5-6

2y=-x-1

2y+x=-x+x-1

x+2y=-1


Therefore, the standard form of 6-2(x-y)=-3x+5 is x+2y=-1.

Answer:  The correct option is

(A) [tex]x+2y=-1.[/tex]

Step-by-step explanation:  We are given to select the option that shows the following equation in standard form :

[tex]6-2(x-y)=-3x+5~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

We know that

the standard form of the equation of a line is ax + by = c.

From equation (i), we get

[tex]6-2(x-y)=-3x+5\\\\\Rightarrow 6-2x+2y=-3x+5\\\\\Rightarrow 6-2x+2y+3x=5\\\\\Rightarrow x+2y=5-6\\\\\Rightarrow x+2y=-1.[/tex]

Thus, the required standard form of the equation of line is [tex]x+2y=-1.[/tex]

Option (A) is CORRECT.

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