Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Ask your questions and receive precise answers from experienced professionals across different disciplines. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Suppose there is a game of chance that you would like to play. It costs $3 to play one time. There are 100 $1 bills, 20 $5 bills, 3 $20 bills, and 1 $100 bill in a box. You may reach into a box without looking and select one bill. Is this a fair game? Why or why not?

Sagot :

Answer:

1. It is not a fair game.

2. The game is not fair because the probability of winning and the probability of losing are not equal.  In a fair game, the probability of winning is equal to the probability of losing.  In this game, the probability of losing is 0.81 or 81%, while the probability of winning is 19% (100 - 81).

Step-by-step explanation:

Cost of playing the game one time = $3

Total number of bills in the box = 124 (100+20+3+1)

Chance of losing is represented by 100 of $1 bills = 100/124 = 0.81 or 81%

Chances of losing are represented by 20 of $5 bills, 3 of $20 bills, and 1 $100 bill = 0.19 or 19% (20/124 + 3/124 + 1/124).