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The length of a rectangle is one more than five times its width. If a perimeter is 38, find the dimensions . Show work .

Sagot :

luana
[tex]x-width\\5x+1-length\\\\2x+2(5x+1)=38\\\\2x+10x+2=38\\\\2x+10x=38-2\\\\12x=36\ \ \ \ \ \ |:12\\\\x=3\\\\5\cdot3+1=15+1=16\\\\Dimensions:\ 3\ and\ 16[/tex]
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