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Sagot :
Answer:
When I got this question I had to draw it out so if you have to do that, draw 3 stick figures holding hands, one representing the mother, father, and daughter. Then you write their weights on top of them and then draw an arrow pointing from the father to the mother.
Explanation:
use this formula :
[tex]a_{y}[/tex] = [tex]\frac{Fdadshandy}{msys}[/tex]
then you fill it in :
[tex]a_{y}[/tex] = [tex]\frac{100N}{35.5kg+58.2kg}[/tex]
[tex]a_{y}[/tex] = [tex]\frac{100N}{93.7kg}[/tex]
[tex]a_{y}[/tex] = [tex]1.0672[/tex] [tex]m/s^{2}[/tex]
then you multiply that with the daughters weight :
[tex]T_{2} x= m_{2} a_{y}[/tex]
[tex]T_{2} x = 35.5kg (1.0672 m/s^{2})[/tex]
[tex]T_{2} x = 37.89N[/tex]
and that's the answer :) : 37.89N
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