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In ΔNOP, \overline{NP}
NP
is extended through point P to point Q, \text{m}\angle NOP = (3x+8)^{\circ}m∠NOP=(3x+8)
∘
, \text{m}\angle PNO = (2x+9)^{\circ}m∠PNO=(2x+9)
∘
, and \text{m}\angle OPQ = (8x-16)^{\circ}m∠OPQ=(8x−16)
∘
. What is the value of x?x?

Sagot :

kouldfingers

Answer:

x=11

Step-by-step explanation:

Using the Exterior Angle Theorem. . .

(3x+8) + (2x+9) = (8x-16)

Solve to get x = 11

drewman1200

Answer:

x=8

Step-by-step explanation:

deltamath

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