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I need help with this Geometry question

I Need Help With This Geometry Question class=

Sagot :

Answer: A) 6 in^2

First, you need to find the length of the base.

a = 3, b = ?, c= 5

Using Pythagorean Theorem*: a^2 + b^2 = c^2

b^2 = c^2 - a^2

b^2 = 5^2 - 3^2

b^2 = 25 - 9

b^2 = 16 (square root both sides)

b = 4

Now, you have to find the area using the area of a triangle formula: A = (bh)/2

A = (bh)/2

A = (4·3)/2

A = 12/2

A = 6 in^2

Pythagorean Theorem is used for this question since it's a right triangle.

Answer: A) 6in^2

Step-by-step explanation:

base = 4 in

height = 3 in (pythagorean theorem)

A = (bxh)/2 = (4x3)/2 = 12/2 = 6 in^2