Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Pounds of gold ore : 11,02311
Further explanation
Given
5 g of gold
0.1% gold by mass
Required
Pounds of gold ore
Solution
[tex]\tt \%mass~gold=\dfrac{mass~gold}{mass~ore}\times 100\%[/tex]
For percent mass = 0.1%, than mass of gold ore :
[tex]\tt 0.1\%=\dfrac{5~g}{mass~ore}\times 100\%\\\\mass~ore=\dfrac{5\times 100}{0.1}\\\\mass~ore=5000~g[/tex]
Conversion factor :
1 g = 0,00220462 pound, than for 5000 g = 11,02311 pounds
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.