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How many pounds of gold ore would need to be processed to obtain 5 grams of gold (Au) if the ore is 0.1% gold by mass?

Sagot :

Pounds of gold ore :  11,02311

Further explanation

Given

5 g of gold

0.1% gold by mass

Required

Pounds of gold ore

Solution

[tex]\tt \%mass~gold=\dfrac{mass~gold}{mass~ore}\times 100\%[/tex]

For percent mass = 0.1%, than mass of gold ore :

[tex]\tt 0.1\%=\dfrac{5~g}{mass~ore}\times 100\%\\\\mass~ore=\dfrac{5\times 100}{0.1}\\\\mass~ore=5000~g[/tex]

Conversion factor :

1 g = 0,00220462 pound, than for 5000 g = 11,02311 pounds

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