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Answer:

Simplifying the expression [tex](3\:.\:2)^5\div (3^2\:.\:2^3)[/tex] so, there is only one power of each base we get [tex]\mathbf{3^3\:.\:2^2}[/tex]

Option D is correct answer.

Step-by-step explanation:

We need to simply the expression [tex](3\:.\:2)^5\div (3^2\:.\:2^3)[/tex] so, there is only one power of each base.

Solving:

[tex](3\:.\:2)^5\div (3^2\:.\:2^3)[/tex]

We can write it as:

[tex]\frac{(3\:.\:2)^5}{3^2.2^3}[/tex]

Now using exponent rule: [tex](a\:.\:b)^m=a^m\:.\:b^n[/tex]

[tex]\frac{3^5\:.\:2^5}{3^2.2^3}[/tex]

Now using the exponent rule: [tex]\frac{a^m}{a^n}=a^{m-n}[/tex] the bases should be same

[tex]3^{5-2}\:.\:2^{5-3}\\=3^3\:.\:2^2[/tex]

So, simplifying the expression [tex](3\:.\:2)^5\div (3^2\:.\:2^3)[/tex] so, there is only one power of each base we get [tex]\mathbf{3^3\:.\:2^2}[/tex]

Option D is correct answer.

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