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If z>0, what is the quotient of 20√z6 ÷ √16z7 in simplest radical form

Sagot :

Answer:

5√z/z

Step-by-step explanation:

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The quotient of [tex]20\sqrt{z^{6} }[/tex] ÷ [tex]\sqrt{16z^{7} }[/tex] in simplest radical form is  [tex]\frac{5\sqrt{z} }{z}[/tex].

How to express a simplest radical form?

Expressing in simplest radical form just means simplifying a radical so that there are no more square roots, cube roots, 4th roots, etc left to find. It also means removing any radicals in the denominator of a fraction.

Given

[tex]20\sqrt{z^{6} }[/tex] ÷ [tex]\sqrt{16z^{7} }[/tex]

Rewrite as fraction: [tex]\frac{20\sqrt{z^{6} } }{\sqrt{16z^{7} } }[/tex]

Factor and rewrite the radicand in exponential form: [tex]\frac{20\sqrt{z^{6} } }{\sqrt{4^{2}. z^{6} .z} }[/tex]

Rewrite the expression using [tex]\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}[/tex] :

= [tex]\frac{20\sqrt{z^{6} } }{\sqrt{4^{2} .\sqrt{z^{6}.\sqrt{z} } } }[/tex]

Simply the radical expression, we get:

= [tex]\frac{20z^{3} }{4z^{3}\sqrt{z} }[/tex]

Reduce fraction to the lowest term by canceling the greater common factor, we get

= [tex]\frac{5}{\sqrt{z} }[/tex]

Rationalize the denominator

= [tex]\frac{5\sqrt{z} }{\sqrt{z} .\sqrt{z} }[/tex]

= [tex]\frac{5\sqrt{z} }{z}[/tex]

Hence, the quotient of [tex]20\sqrt{z^{6} }[/tex] ÷ [tex]\sqrt{16z^{7} }[/tex] in simplest radical form is  [tex]\frac{5\sqrt{z} }{z}[/tex].

Find out more information about simplest radical form here

https://brainly.com/question/12966955

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