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A compound is found to contain 64.80 % carbon, 13.62 % hydrogen, and 21.58 % oxygen by weight. To answer the questions, enter the elements in the order presented above. 1. What is the empirical formula for this compound

Sagot :

sebassandin

Answer:

[tex]C_{4}H_{10}O[/tex]

Explanation:

Hello!

In this case, since the empirical formula of compounds whose by-mass compositions are known, is computed by first computing the moles considering those compositions as actual masses:

[tex]n_C=\frac{64.82g}{12.01g/mol}=5.40mol\\\\n_H=\frac{13.62g}{1.01g/mol}=13.5mol\\\\n_O=\frac{21.58g}{16g/mol}=1.35mol[/tex]

Next, we divide each moles by the fewest ones, in this case those of oxygen to obtain the subscript in the empirical formula:

[tex]C=\frac{5.40}{1.35}= 4\\\\H=\frac{13.5}{1.35}=10\\\\O=\frac{1.35}{1.35}=1[/tex]

Thus, we obtain:

[tex]C_{4}H_{10}O[/tex]

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