laurenthetutor
Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

36x^3 +27x^2=0 pls help me solve :/​

Sagot :

Answer:          36x^3 +27x^2 = 9x^2\left(4x+3\right)

Step-by-step explanation: apply exponent rule rewrite factor out common term plz enjoy

Tekashii

Answer:

[tex]x = 0\; ,-\frac{3}{4}[/tex]

Step-by-step explanation:

[tex]36x^3 + 27x^2 = 0[/tex]

  • Take 9x² common from the expression on L.H.S.

[tex]=> 9x^2(4x + 3) = 0[/tex]

Here, x will have 2 values :-

1) [tex]9x^2(4x + 3) = 0[/tex]

  • Divide both the sides by (4x + 3)

[tex]=> \frac{9x^2(4x + 3)}{(4x+3)} = \frac{0}{4x+3}[/tex]

[tex]=> 9x^2 = 0[/tex]

  • Divide both the sides by 9x

[tex]=> \frac{9x^2}{9x} = \frac{0}{9x}[/tex]

[tex]=> x = 0[/tex]

2) [tex]9x^2(4x + 3) = 0[/tex]

  • Divide both the sides by 9x²

[tex]=> \frac{9x^2(4x + 3)}{9x^2} = \frac{0}{9x^2}[/tex]

[tex]=> 4x+3 = 0[/tex]

  • Substract both the sides from 3

[tex]=> 4x+3 -3 = 0 - 3[/tex]

[tex]=> 4x=-3[/tex]

  • Divide both the sides by 4

[tex]=> \frac{4x}{4} = \frac{-3}{4}[/tex]

[tex]=> x = -\frac{3}{4}[/tex]

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.