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What is the pH of a 2.4 x 10-5 M
OH-solution?


Sagot :

Answer: pH = 9.4

Explanation: in water, -log(molar concentration OH-) + -log(molar concentration H+) = 14

-log(H+) is pH

so pH = 14 - -log(OH-)

= 14 - -log(2.4*10^-5)

= 14 - 4.6

= 9.4