At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Answer: The empirical formula is [tex]H_4P_2O_7[/tex]
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of H= 2.270 g
Mass of P = 34.80 g
Mass of O = 62.93 g
Step 1 : convert given masses into moles
Moles of H = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{2.270g}{1g/mol}=2.270[/tex]
Moles of P = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{34.80g}{31g/mol}=1.122[/tex]
Moles of O = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{62.93g}{16g/mol}=3.933[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For H = [tex]\frac{2.270}{1.122}=2[/tex]
For P= [tex]\frac{1.122}{1.122}=1[/tex]
For O = [tex]\frac{3.933}{1.122}=3.5[/tex]
The simples ratio will be = H: P : O= 4: 2: 7
Hence the empirical formula is [tex]H_4P_2O_7[/tex]
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.