Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer: The empirical formula is [tex]H_4P_2O_7[/tex]
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of H= 2.270 g
Mass of P = 34.80 g
Mass of O = 62.93 g
Step 1 : convert given masses into moles
Moles of H = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{2.270g}{1g/mol}=2.270[/tex]
Moles of P = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{34.80g}{31g/mol}=1.122[/tex]
Moles of O = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{62.93g}{16g/mol}=3.933[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For H = [tex]\frac{2.270}{1.122}=2[/tex]
For P= [tex]\frac{1.122}{1.122}=1[/tex]
For O = [tex]\frac{3.933}{1.122}=3.5[/tex]
The simples ratio will be = H: P : O= 4: 2: 7
Hence the empirical formula is [tex]H_4P_2O_7[/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
