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Sagot :
Explanation:
Given parameters:
Frequency = 12Hz
Unknown:
a. Period of its rotation
b. Time required to complete 86 rotations
Solution:
Frequency is the number of times of rotation per unit of time.
Frequency = [tex]\frac{n}{t}[/tex]
Period is the opposite of frequency;
Period = [tex]\frac{1}{12}[/tex] = 0.083s
b. Time for 86 rotations;
Since frequency = [tex]\frac{n}{t}[/tex]
n is the number of rotation
t is the time
t = [tex]\frac{n}{Frequency}[/tex] = [tex]\frac{86}{12}[/tex] = 7.2s
The period of rotation is 1/12 seconds and it takes 7.17 seconds to complete 86 rotations.
Time period (T) in a rotational or periodic motion is defined as the time taken to complete one rotation and frequency (f) is the reciprocal of time period.
f = 1/T ⇒ T = 1/f , given that f = 12 Hz
T = 1/12 s is the time period of ne rotation
Now if time takes to complete one rotation is 1/12s , then to complete 86 rotation, the time required is
t = 86×(1/12) = 7.17 seconds is taken to complete 86 rotations.
Learn more about periodic motion:
https://brainly.com/question/17960431?referrer=searchResults
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