Answered

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When a process is in control, it results in there being, on average, 16 defects per unit of output. c-chart limits of 8 and 24 would lead to a

Sagot :

ajeigbeibraheem

Answer:

4.56%

Explanation:

From the given information:

In a c-chart limit

UCL = [tex]\bar c+ z \times \sqrt{\bar c }[/tex]

where;

[tex]\bar c = 16[/tex]

UCL = 24

Then:

[tex]24 = 16 + z \times \sqrt{24}[/tex]

[tex]24 -1 6 = z \times \sqrt{24}[/tex]

[tex]8 = z \times 4.89[/tex]

[tex]z = \dfrac{8}{4.89}[/tex]

z [tex]\simeq[/tex] 2.0

At z = 2.0, the value represents the probability of 95.44% of not making a Type 1 error.

This implies that the probability of making a Type 1 error = 1 - 95.44%

= 4.56%

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