At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

A. 5/7 pi

B. 4/9 pi

C. 6/7 pi

D. 2/3 pi

E. 5/9 pi


A 57 Pi B 49 Pi C 67 Pi D 23 Pi E 59 Pi class=

Sagot :

Answer:

A. 2.243994753

B. 1.396263402

C. 2.692793703

D. 2.094395102

E. 1.745329252

Answer:

D

Step-by-step explanation:

Remark

This is an incredibly beautiful problem! It is solved mostly by algebra. r = 1 and the height will therefore be 2

Equations

l^2 + r^2 = l^2

l is the slant height.

Solution

SA = π * l * r + π r² = π(1 + √5)          Divide both sides by π

Find l

l * r + r^2 = 1 + √5

l^2 = r^2  + h^2

l^2 = r^2 + (2r)^2

l^2 = 5r^2

l = √5 * r

Now go back to this equation to find r

l * r + r^2 = 1 + √5                               Substitute the value for l

√5 r * r + r^2 = 1 + √5                         On the left pull out r^2

r^2 (1 + √5) = 1 + √5                            Divide by 1 + √5

r^2 = 1                                                  Take the square root on both sides

sqrt(r^2) = sqrt(1)

r =1

Therefore h = 2

Volume of the cone.

V = 1/3 * π r² h

V = 1/3 * π 1² 2

V = 2/3 * pi

D