cheesymary
Answered

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what is an equation of the line that passes through the point (-6,-1) and is perpendicular to the line 6x-y=7? (has to be in y=mx+b form)

Sagot :

xenia168

Answer:

y = [tex]-\frac{1}{6}[/tex] x - 2

Step-by-step explanation:

Slopes of perpendicular lines are opposite reciprocals.

If AB ⊥ CD , then [tex]m_{AB}[/tex] [tex]m_{CD}[/tex] = - 1

y - [tex]y_{1}[/tex] = m(x - [tex]x_{1}[/tex])

~~~~~~~~~~~

6x - y = 7 ⇔ y = 6x - 7

Slope of given line is 6

Slope of a perpendicular line is [tex]-\frac{1}{6}[/tex]

( - 6, - 1 )

y + 1 = [tex]-\frac{1}{6}[/tex] (x + 6)

y = [tex]-\frac{1}{6}[/tex] x - 2

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