chloeannashin
Answered

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Bring 8/(a-x) to a denominator of x-a

Sagot :

CSMedrano

Answer:

[tex]-\frac{8}{x-a}[/tex]

Step-by-step explanation:

[tex]\frac{8}{a-x}[/tex]

we can take common factor of -1 in the denominator

[tex]\frac{8}{-(-a+x)}=\frac{8}{-(x-a)}[/tex]

and now multiply and divide by -1

[tex]\frac{8}{-(x-a)}\cdot \frac{-1}{-1}=\frac{-8}{x-a}=-\frac{8}{x-a}[/tex]

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