Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Given:
Area of a rectangle is [tex]600 \text{cm}^2[/tex].
Breadth is two-third of its length.
To find:
The length and breadth of the rectangle .
Solution:
Let x cm be the length of the rectangle.
Then, Breadth or width of the rectangle = [tex]\dfrac{2}{3}x[/tex] cm
Area of a rectangle is
[tex]Area=Length \times Breadth[/tex]
[tex]600=x \times \dfrac{2}{3}x[/tex]
[tex]600=\dfrac{2}{3}x^2[/tex]
Multiply both sides by 3.
[tex]1800=2x^2[/tex]
Divide both sides by 2.
[tex]900=x^2[/tex]
Taking square root on both sides.
[tex]\pm \sqrt{900}=x[/tex]
[tex]\pm 30=x[/tex]
Length cannot be negative. So, x=30.
Now,
Length = [tex]30\text{ cm}[/tex]
Breadth = [tex]\dfrac{2}{3}\times 30\text{ cm}[/tex]
= [tex]2\times 10\text{ cm}[/tex]
= [tex]20\text{ cm}[/tex]
Therefore, the length of the rectangle is 30 cm and the breadth is 20 cm.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
