[tex]\boxed{\boxed{\pink{\sf \leadsto The \ x - intercept \ is \ (2,0) \ \& \ the \ y \ intercept \ is \ (-8,0) }}}[/tex]
A linear equation is given to us and we are required to find x and y Intercepts to it. So the given linear equation to us is ,
[tex]\bf \implies 4x - y = 8 \\\\\bf\implies \dfrac{1}{8} \bigg( 4x -y\bigg) =\frac{1}{8}\times 8 \\\\\bf\implies \dfrac{4x}{8}-\dfrac{y}{8} = \dfrac{8}{8} \\\\\bf\implies \dfrac{x}{2}-\dfrac{y}{8}=1 \\\\\bf\implies\boxed{\red{\bf \dfrac{x}{2}+\dfrac{y}{-8}=1 }}[/tex]
Hence on comparing to standard form we get
Answer:
x = (2,0)
y = (0,-8)
Step-by-step explanation:
Remember than an intercept always has the other number as 0.
Let's put this in standard form of a linear equation, or y = mx + b
4x - y = 8
-y = -4x + 8
y = 4x - 8
"b" is the y intercept. The y intercept is -8, or (0,-8)
Now, to find the x intercept, all we have to do is substitute 0 for y.
0 = 4x -8
8 = 4x
2 = x
The x intercept is 2, or (2,0)
