At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Given:
The base of 40-foot ladder is 8 feet from the wall.
To find:
How high is the ladder on the wall (round to the nearest foot).
Solution:
Ladder makes a right angle triangle with wall and ground.
We have,
Length of ladder (hypotenuse)= 40 foot
Base = 8 foot
We need to find the perpendicular to get the height of the ladder on the wall.
Let h be the height of the ladder on the wall.
According to the Pythagoras theorem,
[tex]Hypotenuse^2=Base^2+Perpendicular^2[/tex]
[tex](40)^2=(8)^2+(h)^2[/tex]
[tex]1600=64+h^2[/tex]
[tex]1600-64=h^2[/tex]
[tex]1536=h^2[/tex]
Taking square root on both sides.
[tex]\pm \sqrt{1536}=h[/tex]
[tex]\pm 39.1918358=h[/tex]
Height cannot be negative. Round to the nearest foot.
[tex]h\approx 39[/tex]
Therefore, the height of the ladder on the wall is 39 foot.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
