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the probability of randomly selecting a four-person committee consisting entirely of canadians from a pool of 11 americans and 18 canadian

Sagot :

Answer:

[tex]Probability =0.1744[/tex]

Step-by-step explanation:

Given

Total

[tex]American = 11[/tex]

[tex]Canadian = 18[/tex]

Selection

[tex]American = 0[/tex]

[tex]Canadian = 4[/tex]

Required

Determine the probability of selecting a 4 committee member that are Canadian.

First, we calculate total possible selection.

[tex]Total = American + Canadian[/tex]

[tex]Total = 11 + 18[/tex]

[tex]Total = 27[/tex]

Number of ways to select 4 from 27 is:

[tex]^{27}C_4 = \frac{27!}{(27-4)!4!}[/tex]

[tex]^{27}C_4 = \frac{27!}{23!4!}[/tex]

[tex]^{27}C_4 = \frac{27*26*25*24*23!}{23!4!}[/tex]

[tex]^{27}C_4 = \frac{27*26*25*24}{4!}[/tex]

[tex]^{27}C_4 = \frac{27*26*25*24}{4*3*2*1}[/tex]

[tex]^{27}C_4 = \frac{421200}{24}[/tex]

[tex]^{27}C_4 = 17550[/tex]

Next, we calculate ways of selecting 4 Canadians from 18 is:

[tex]^{18}C_4 = \frac{18!}{(18-4)!4!}[/tex]

[tex]^{18}C_4 = \frac{18!}{14!4!}[/tex]

[tex]^{18}C_4 = \frac{18*17*16*15*14!}{14!4!}[/tex]

[tex]^{18}C_4 = \frac{18*17*16*15}{4!}[/tex]

[tex]^{18}C_4 = \frac{18*17*16*15}{4*3*2*1}[/tex]

[tex]^{18}C_4 = \frac{73440}{24}[/tex]

[tex]^{18}C_4 = 3060[/tex]

The required probability is:

[tex]Probability =\frac{3060}{17550}[/tex]

[tex]Probability =0.1744[/tex]