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Need to know the following angle

Need To Know The Following Angle class=

Sagot :

Given:

[tex]m\angle A=(2x-15)^\circ[/tex]

[tex]m\angle B=(x-5)^\circ[/tex]

[tex]\text{Exterior}\ m\angle C=148^\circ[/tex]

To find:

The [tex]m\angle ABC[/tex].

Solution:

In triangle ABC,

[tex]\text{Exterior}\ m\angle C=m\angle A+m\angle B[/tex]          [Exterior angle theorem]

[tex]148=(2x-15)+(x-5)[/tex]

[tex]148=3x-20[/tex]

[tex]148+20=3x[/tex]

[tex]168=3x[/tex]

Divide both sides by 3.

[tex]\dfrac{168}{3}=x[/tex]

[tex]56=x[/tex]

Now,

[tex]m\angle ABC=(x-5)^\circ[/tex]

[tex]m\angle ABC=(56-5)^\circ[/tex]

[tex]m\angle ABC=51^\circ[/tex]

Therefore, [tex]m\angle ABC=51^\circ[/tex].