Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

If one of the diagonals of a rectangle is 20cm and the difference between the length and the width is 4cm. What is the area of the triangle

Sagot :

abidemiokin

Answer:

192cm²

Step-by-step explanation:

The diagonal of the rectangle is expressed using the formula:

d = √l²+w²

l is the length

w is the width

Given d = 20

20 = √l²+w²

400 = l²+w² .... 1

Since the difference between the length and the width is 4cm, then;

l - w = 4 ... 2

l = 4 + w

Substitute equation 2 into 1;

400 = (4+w)²+w²

400 = 16 +8w + w² +w²

400 = 16 + 8w + 2w²

2w²+8w - 384 = 0

w²+4w - 192 = 0

w = -4±√4²-4(-192)/2

w = -4±√16+768/2

w = -4±28/2

w = -4+28/2

w = 24/2

w = 12

Since l = w+4

l = 12+4

l = 16

Area of the rectangle = 16 * 12

Area of the rectangle = 192cm²

Answer:

rytytyf

Step-by-step explanation:

yiyiuyiuy

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.