Answered

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A family requires 20,000 KJ of fuel energy every day. If calorific vlaue

of the fuel used by them is 15,000 kJ/kg, how much of this fuel will be

required by this family to meet their energy needs for the month of April?​

Sagot :

xero099

Answer:

40 kilograms of fuel are required to meet their energy needs for the month of April.

Explanation:

The month of April has 30 days and the full energy needed by the family is determine by the following combustion formula, derived from dimension analysis:

[tex]n\cdot Q = m\cdot L_{c}[/tex] (1)

Where:

[tex]m[/tex] - Mass of the fuel, measured in kilograms.

[tex]L_{c}[/tex] - Calorific value of the fuel, measured in kilojoules per kilogram.

[tex]Q[/tex] - Daily fuel energy, measured in kilojoules.

[tex]n[/tex] - Number of days of the month, dimensionless.

If we know that [tex]Q = 20000\,kJ[/tex], [tex]n = 30[/tex] and [tex]L_{c} = 15000\,\frac{kJ}{kg}[/tex], then the amount of fuel required to meet their energy needs for the month of April is:

[tex]m = \frac{n\cdot Q}{L_{c}}[/tex]

[tex]m = \frac{(30)\cdot (20000\,kJ)}{15000\,\frac{kJ}{kg} }[/tex]

[tex]m = 40\,kg[/tex]

40 kilograms of fuel are required to meet their energy needs for the month of April.

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