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Finding Solutions
The solution is k =
Use the work shown below to solve.
1. Identify the operation in the equation
2. Use inverse operations to solve,
Subtraction property of equality
=k+11
13
2
2
15
2
Addition property of equality
+(-)=k+1+(-)


Finding Solutions The Solution Is K Use The Work Shown Below To Solve 1 Identify The Operation In The Equation 2 Use Inverse Operations To Solve Subtraction Pro class=

Sagot :

Answer:

[tex]k = -4[/tex]

Step-by-step explanation:

Given

[tex]\frac{3}{2} = k + \frac{11}{2}[/tex]

Required

Solve for k

[tex]\frac{3}{2} = k + \frac{11}{2}[/tex]

Apply subtraction property

[tex]\frac{3}{2} - \frac{11}{2} = k + \frac{11}{2} - \frac{11}{2}[/tex]

Apply addition property

[tex]\frac{3}{2} +(- \frac{11}{2}) = k + \frac{11}{2} +(- \frac{11}{2} )[/tex]

The fractions on the right represent an additive inverse.

So, we have:

[tex]\frac{3}{2} +(- \frac{11}{2}) = k[/tex]

Take LCM

[tex]\frac{3+(-11)}{2} = k[/tex]

Remove bracket

[tex]\frac{3-11}{2} = k[/tex]

[tex]\frac{-8}{2} = k[/tex]

[tex]-\frac{8}{2} = k[/tex]

[tex]-4 = k[/tex]

[tex]k = -4[/tex]

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