mclargo7
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

could someone help me with this please? thank you

Could Someone Help Me With This Please Thank You class=

Sagot :

Answer:

x1 = 0.52

x2 = -10.1

x3 = 0.97

Step-by-step explanation:

From the question;

x1 = 1 - 3/(x0)^2

x0 = -2.5

x1 = 1- 3/(-2.5)^2

x1 = 1 -0.48

x1 = 0.52

x2 = 1 - 3/(x1)^2

x2 = 1 - 3/0.52^2

x2 = 1 - 11.1

x2 = -10.1

x3 = 1 - 3/(x2)^2

x3 = 1- 3/(-10.1)^2

x3 = 0.97

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.