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Sagot :
Explanation:
Rubidium is in Group 1 and exists as Rb+ ions.
Sulfur is in Group 16 and exists as S2- ions.
To form a compound containing rubidium and sulfur, the charges of the ions must be equal.
Therefore there are 2 rubidium and 1 sulfur atoms.
=> Chemical formula is Rb2S.
Sodium is also in Group 1 and exists as Na+ ions.
Oxygen is also in Group 16 and exists as O2- ions.
Therefore there are 2 sodium and 1 oxygen atoms.
=> Chemical formula is Na2O.
The chemical formula of the compounds form are as follows;
- For Rubidium and sulfur; Rb2S
- For Sodium and oxygen; Na20
Discussion:
- Rubidium, Rb is in Group 1 and ionises as Rb+ ions.
- Sulfur, S is in Group 16 and ionises as S2- ions.
To form a compound between rubidium and sulfur, the net charge must be zero
As a result, we need 2 rubidium and 1 sulfur atoms.
- Chemical formula is therefore; Rb2S.
Similarly, Sodium, Na is in Group 1 and ionises as Na+ ions.
Oxygen, O is in Group 16 and ionises as O2- ions.
To form a compound between Sodium and Oxygen, the net charge must be zero
As a result, we need 2 Sodium and 1 Oxygen atoms.
- Chemical formula is therefore; Na2O.
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