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Explain how to find the combining ratio and chemical formula between the following pairs of elements using the periodic table:
-Rubidium and sulfur
-Sodium and oxygen
Please explain your answer and dont answer if you dont know

Sagot :

ChoiSungHyun

Explanation:

Rubidium is in Group 1 and exists as Rb+ ions.

Sulfur is in Group 16 and exists as S2- ions.

To form a compound containing rubidium and sulfur, the charges of the ions must be equal.

Therefore there are 2 rubidium and 1 sulfur atoms.

=> Chemical formula is Rb2S.

Sodium is also in Group 1 and exists as Na+ ions.

Oxygen is also in Group 16 and exists as O2- ions.

Therefore there are 2 sodium and 1 oxygen atoms.

=> Chemical formula is Na2O.

adioabiola

The chemical formula of the compounds form are as follows;

  • For Rubidium and sulfur; Rb2S

  • For Sodium and oxygen; Na20

Discussion:

  • Rubidium, Rb is in Group 1 and ionises as Rb+ ions.

  • Sulfur, S is in Group 16 and ionises as S2- ions.

To form a compound between rubidium and sulfur, the net charge must be zero

As a result, we need 2 rubidium and 1 sulfur atoms.

  • Chemical formula is therefore; Rb2S.

Similarly, Sodium, Na is in Group 1 and ionises as Na+ ions.

Oxygen, O is in Group 16 and ionises as O2- ions.

To form a compound between Sodium and Oxygen, the net charge must be zero

As a result, we need 2 Sodium and 1 Oxygen atoms.

  • Chemical formula is therefore; Na2O.

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