Answer:
It required 3 cones to fill up the cylinder with the same height and diameter.
Step-by-step explanation:
Let the radius of the cone and cylinder be r.
Let the height of the cone and cylinder be h.
As we know that [tex]\text{Volume of cylinder}=\pi r^2h[/tex] ....(1)
[tex]\text{Volume of cone}=\frac{1}{3}\pi r^2h[/tex]
It can be observed that the volume of a cone is [tex]\frac{1}{3}[/tex]rd the volume of the cylinder. so, multiply the volume of the cone by 3.
[tex]3 \times \text{Volume of cone}=3 \times \frac{1}{3}\pi r^2h[/tex]
[tex]3 \times \text{Volume of cone}= \pi r^2h[/tex]
[tex]3 \times \text{Volume of cone}= \text{Volume of cylinder}[/tex] (From equation 1 )
Hence, It required 3 cones to fill up the cylinder with the same height and diameter.