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Sagot :
Answer:
General solution x = log | sec y | + C
Step-by-step explanation:
Step(i):-
Given
[tex]e^{x} cosy dx - e^{x} sin y d y = 0[/tex]
[tex]e^{x} (cosy dx = e^{x} sin y d y[/tex]
cos y dx = sin y d y
[tex]dx = tan y d y[/tex]
Step(ii):-
now integrating on both sides , we get
[tex]\int\limits {1} \, dx = \int\limits {tany} \, dy[/tex]
by using formula
[tex]\int\limits {tany} \, dy = log | sec y | + C[/tex]
x = log | sec y | + C
Final answer:-
General solution x = log | sec y | + C
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